angle bisectorの例文

• An angle bisector divides the angle into two angles with equal measures.
• Each point of an angle bisector is equidistant from the sides of the angle.
• Rays have one angle bisector; lines have two, perpendicular to one another.
• No two non-congruent triangles share the same set of three internal angle bisector lengths.
• The intersection of the circles ( two points ) determines a line that is the angle bisector.
• Also the altitude having the incongruent side as its base will form the angle bisector of the vertex.
• Three intersection points, each of an external angle bisector with the opposite extended side, are collinear ( fall on the same line as each other ).
• Indeed, if it were possible to accelerate an observer to the speed of light, then the space and time axes would coincide with their angle bisector.
• *PM : compass and straightedge construction of angle bisector, id = 9502 new !-- WP guess : compass and straightedge construction of angle bisector-- Status:
• *PM : compass and straightedge construction of angle bisector, id = 9502 new !-- WP guess : compass and straightedge construction of angle bisector-- Status:
• Two circles of the same radius, centered on T1 and T2, intersect at points P and Q . The line through P and Q ( 1 ) is an angle bisector.
• :: : : : : : If the point is on an angle bisector, its isogonal conjugate is on the other side of the incenter, never on the same side.
• Three intersection points, two of them between an interior angle bisector and the opposite side, and the third between the other exterior angle bisector and the opposite side extended, are collinear.
• Three intersection points, two of them between an interior angle bisector and the opposite side, and the third between the other exterior angle bisector and the opposite side extended, are collinear.
• Yes, I've read teh angle bisector article and looked at the proofs . my proof doesn't use any trig functions, which is why i think it might be original-JianLi
• In any triangle, if P is on an angle bisector, P'will be on the same angle bisector but on the other side of the incenter, giving angle PIP'= 180?
• In any triangle, if P is on an angle bisector, P'will be on the same angle bisector but on the other side of the incenter, giving angle PIP'= 180?
• To solve this problem, the center of any such circle must lie on an angle bisector of any pair of the lines; there are two angle-bisecting lines for every intersection of two lines.
• In a triangle, three intersection points, two of them between an interior angle bisector and the opposite side, and the third between the other exterior angle bisector and the opposite side extended, are collinear.
• In a triangle, three intersection points, two of them between an interior angle bisector and the opposite side, and the third between the other exterior angle bisector and the opposite side extended, are collinear.